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0=5x^2-120x+700
We move all terms to the left:
0-(5x^2-120x+700)=0
We add all the numbers together, and all the variables
-(5x^2-120x+700)=0
We get rid of parentheses
-5x^2+120x-700=0
a = -5; b = 120; c = -700;
Δ = b2-4ac
Δ = 1202-4·(-5)·(-700)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-20}{2*-5}=\frac{-140}{-10} =+14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+20}{2*-5}=\frac{-100}{-10} =+10 $
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